3m^2+2m-8=2

Solution for 3m^2+2m-8=2 equation:

3m^2+2m-8=2

We move all terms to the left:

3m^2+2m-8-(2)=0

We add all the numbers together, and all the variables

3m^2+2m-10=0

a = 3; b = 2; c = -10;
Δ = b2-4ac
Δ = 22-4·3·(-10)
Δ = 124
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{124}=\sqrt{4*31}=\sqrt{4}*\sqrt{31}=2\sqrt{31}$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2\sqrt{31}}{2*3}=\frac{-2-2\sqrt{31}}{6}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2\sqrt{31}}{2*3}=\frac{-2+2\sqrt{31}}{6}
$